Appendix III. The Corner Boards

Dr. E. E. Iungerich's solution (Journal of Education, Vol. 15, p. 143.) It is a simple problem in mathematics: Let x and y be the two parts into which the board is to be cut. Then:

x + y = 1¹/₂ or ⁹/₆ cubits

x = ⁹/₆ - y

Since the board is ¹/₆ cubit in thickness, then, if the two legs are to be of equal length when placed together x = y - ¹/₆ . Substituting, we have

y  -  ¹/₆ = ⁹/₆ -  y

2y=⁵/₆

x = ⁴/₆ or ²/₃